Digital Pedometer
word algebra 2 problems?
for 30 minutes you make a combination of walking and jogging. at the end of your workout your pedometer displays a total of 2.5 miles. you know you walk 0.05 mile per minute and 0.1 mile jogging per minute. how long have you been foot? how long have you been jogging? use a verbal model to write and solve a system of linear equations. Directory of school staff is buying a digital camera. Recently, staff received two ads in the mail. Ad for the store 1 states that all digital cameras are 15%. Ad for the store 2 provides a $ 300 voucher to use when you buy any digital camera. Assuming that the lowest digital camera price is $ 700. write and graph two equations that describe the price of two stores. when Is this shop a deal than have a store? 2 better please tell me how to set up the equations as best you can thank you:)
where x is time and y is the march of time spent jogging 0.05x + .1 y = 2.5 and x + y = 30 there are two possible ways to solve this substitution 1: x + y = 30 x = 30-y then replace x 0.05 x + .1 y = 2.5 to yield 0.05 (30-y) + 0.1 = 2.5 solve it as follows: 0.05 (30-y) + y = 0.1 2.5 1.5 0.1 + .05 y-y = 2.5 1.5 +. 05y = 2.5 0.05 0.05 y = 2.5 to 1.5 y = 1 y = (1/.05) y = y = 20 replace 20 in your original equation 0.05 x + 0.1 y = 2.5 x and solve for x 0.05 + 0.1 (20) = 2.5 2 = 2.5 x 0.05 x 0.05 = 2.5 2 x 0.05 x =. 5 = (0.5 /. 05) x = 10 2 elimination take the same 2 equations and zero x or y. in my example I reset them multiply 0.05 x + 0.1 y = 2.5 x 0.05 at -10 + 0.1 = 2.5 there is -. 5x-1a =- 25 x + y = 30 is x + y = 30 subtract one from the other equation x + y = 30 -. 5x-y =- 25 x 0.5 = 5 x = (5/.5) x = 10, insert in one you original equations. I will use x + y = 30 simply because its easier 10 + y = 30 y = (30-10) y = 20 x = y = 10 and 20 so that the time spent to walk 10 minutes and the time spent was 20 minutes of jogging i cannot graph equations on the second question, but ill try my best to explain his simple actually a shop gives a discount of 15% which is equivalent to selling the camera at a cost of 85% of original price. and the second store remits flat $ 300. then let x = the original price of the camera and let y = the discount store is 1 x (0.85) = y or 700 (0.85) = 595 and store 2 is x = y-300 700-300 = 400 to 700 or so for the price of the camera 2 is cheaper store to find out when a store is less expensive then x (0.85)
-.15x<-300
x<2000
so lorsque le prix de la caméra est au-dessus stocker 2000 $ 1 est le moins cher pour ce graphique en utilisant le formulaire Store 1 is the slope intercept y =. 85x Tray 2 is y = x-300
Omron Digital Pedometer Model HJ 112
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